Rotate Image - Leetcode Solution
# Intuition First, we will find the transpose matrix and then swap the first and last columns. # Complexity - Time complexity: O(N^2) - Space complexity: O(1) # Code ``` class Solution { // TC=O(N^2) // SC=O(1) public: void rotate(vector<vector<int>>& matrix) { int n=matrix.size(); //This for loop is used to Transpose the matrix for(int i=0;i<n;i++) { for(int j=0;j<i;j++) { swap(matrix[i][j],matrix[j][i]); } } //This for loop will swap the first column and last column for(int i=0;i<n;i++) { reverse(m...